(x+-3)^2-(2x+5)^2-16=0

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Solution for (x+-3)^2-(2x+5)^2-16=0 equation: 



(x+-3)^2-(2x+5)^2-16=0

We add all the numbers together, and all the variables

(x-3)^2-(2x+5)^2-16=0

We move all terms containing x to the left, all other terms to the right

(x-3)^2-(2x+5)^2=16

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